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An alloy of iron (54.7%) nickel (45%) and manganese (0.3%) has a density of 8.17 g//cm^(3). How many iron atoms are there in a block of alloy measuring 10cmxx20cmxx15cm?

Answer»

Solution :Volume of the block of alloy`=10020xx15cm^(3)`
=`3000cm^(3)`
Mass of the block `=300xx8.17g=24510g`
Mass of iron in the block `=(54.7)/(100)xx24510=13406.97g`
Number of iron atoms in the block `=("Mass")/("Atomic mass")xx6.023xx10^(23)`
`=1.442xx10^(26)`


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