an alloy contains 36 percent zinc,40 percent copper and the rest is ni

1.	an alloy contains 36 percent zinc,40 percent copper and the rest is nickel . find in grams the quantity of each of the contents in a sample of 1 kg alloy
Answer» $\circ\circ\circ\circ\underline{\fbox{\fbox{\fbox{\fbox{\fbox{\Large{\underline{\textbf{SOLUTION}}}}}}}}}\circ\circ\circ\circ$ $Amount\:of\:alloy=1\:kg=1000\:g\\\\Zinc=36\%\\\\Copper=40\%\\\\and\:nickel=100-(36+40)\%\\\\=100-76\\\\=24\%\\\\Amount\:of\:zinc\:=36\%\:of\:1000\:g\\\\=\frac{36}{100}\times1000\\\\=360\:g\\\\Amount\:of\:copper=\frac{40}{100}\times1000\\\\=400\:g\\\\Amount\:of\:nickel=\frac{24}{100}\times1000\\\\=240\:g\\\\\boxed{\boxed{Amount\:of\:zinc=360\:g}}\\\\\boxed{\boxed{Amount\:of\:copper=400\:g}}\\\\\boxed{\boxed{Amount\:of\:nickel=240\:g}}$

an alloy contains 36 percent zinc,40 percent copper and the rest is nickel . find in grams the quantity of each of the contents in a sample of 1 kg alloy

Answer»

$\circ\circ\circ\circ\underline{\fbox{\fbox{\fbox{\fbox{\fbox{\Large{\underline{\textbf{SOLUTION}}}}}}}}}\circ\circ\circ\circ$

$Amount\:of\:alloy=1\:kg=1000\:g\\\\Zinc=36\%\\\\Copper=40\%\\\\and\:nickel=100-(36+40)\%\\\\=100-76\\\\=24\%\\\\Amount\:of\:zinc\:=36\%\:of\:1000\:g\\\\=\frac{36}{100}\times1000\\\\=360\:g\\\\Amount\:of\:copper=\frac{40}{100}\times1000\\\\=400\:g\\\\Amount\:of\:nickel=\frac{24}{100}\times1000\\\\=240\:g\\\\\boxed{\boxed{Amount\:of\:zinc=360\:g}}\\\\\boxed{\boxed{Amount\:of\:copper=400\:g}}\\\\\boxed{\boxed{Amount\:of\:nickel=240\:g}}$

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