An alkyl halide with beta-hydrogen atoms on reaction with a base or a nucleophile has two competing paths. Substitutions (S_(N^(1)) and S_(N^(2))) and elimination (E_(1) and E_(2)). The path adopted by them depends upon the nature of the alkyl halide, strength and size of the base/nucleophile and reaction conditions. The bulkiers nucleophile prefers to act as a base and abstracts a proton rather than approaching a tetravalent carbon atom (due to steric reasons) and vise versa. A primary alkyl halide can react by any of the four mechanism (S_(N^(2)), S_(N^(1)), E_(2) and E_(1)) depending upon the stability or the intermediate carbocation or the substituted alkene formed and the reaction conditions and tertiary alkyl halide. The three possible paths (S_(N^(1)), E_(1) and E_(2)) 2-Bromopropane is separately heated with aq CH_(3)CO_(2)Na or with CH_(3)CH_(2)ONa//CH_(3)CH_(2)OH. The majorproduct obtained in each caserespectively are

An alkyl halide with beta-hydrogen atoms on reaction with a base or a

1.	An alkyl halide with beta-hydrogen atoms on reaction with a base or a nucleophile has two competing paths. Substitutions (S_(N^(1)) and S_(N^(2))) and elimination (E_(1) and E_(2)). The path adopted by them depends upon the nature of the alkyl halide, strength and size of the base/nucleophile and reaction conditions. The bulkiers nucleophile prefers to act as a base and abstracts a proton rather than approaching a tetravalent carbon atom (due to steric reasons) and vise versa. A primary alkyl halide can react by any of the four mechanism (S_(N^(2)), S_(N^(1)), E_(2) and E_(1)) depending upon the stability or the intermediate carbocation or the substituted alkene formed and the reaction conditions and tertiary alkyl halide. The three possible paths (S_(N^(1)), E_(1) and E_(2)) 2-Bromopropane is separately heated with aq CH_(3)CO_(2)Na or with CH_(3)CH_(2)ONa//CH_(3)CH_(2)OH. The majorproduct obtained in each caserespectively are
Answer» ISOPROPYL acetate, propene Propane, isopropylethyl ether Isopropyl acetate, isopropyl ethyl ether Propene in both the case Solution :`CH_(3)COO^(-)` is a weak base and hence brings about SUBSTITUTIONS while `C_(2)H_(5)O^(-)` is a strong base and hence bring about ELIMINATIONS.