1.

An alkyl halide of formula C_(4)H_(9)Cl on treatement with alcoholic potash gives alkenes C_(4)H_(8). Both alkenes on tratment with HI gives 2-iodo butate. Isomeric alkenes are

Answer»

`CH_(3)CH_(2)CH=CH_(2) and CH_(3)CH=CHCH_(3)`
`CH_(3)CH_(2)=CH_(2) and (CH_(3))_(2)C=CH_(2)`
`CH_(3)CH=CH_(2) and CH_(3) CH=CHCH_(3)`
`CH_(3)CH_(2)CH=CH_(2) and CH_(3)CH=CH_(2)`

Solution :Because rate of reaction depends upon concentration of anly `3^(@)` alkyl halide not on concentration of aq. Potash.
(a) Molecular FORMULA `C_(4)H_(9)CL` has four isomers, thses are n-BUTYL chloride,sec. butyl chloride. Former twoon elimination gives 1-butene and 2-butene respectively and latter two on elimination gives siobutylene. 1-butene and 2-butene are treated withHI gives 2-iodobutane. 1-butene and 2-butene are POSITION isomers. Isobutylene is treated with HI gives t-butyl iodide hence answer is (a)


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