1.

An alkane withmolecularmass 72 formed only one substitution product .Suggest a structure for thealkane .

Answer»

Solution :Letthemolecularformula of thealkane be`C_(n)H_(2n+2).`
Molecular mass of thealane `nC+(2n+2)H`
`=nxx12+(2n+2)xx1`
`=14n+2`
`thus,14n+2=72`
or `14n=72-2=70`
SO, `n=(70)/(14)=5`
thus , the molecularformulaof thealkane is `C_(5)H_(12). ` It canthavethreeisomers .
`underset("n- Pentane")(CH_(3)CH_(2)CH_(2)CH_(3)),CH_(3)underset(("isopentane"))underset("2-Methylbutane ")OVERSET(CH_(3))overset(|)(CH_(3)CHCH_(2)CH_(3)),CH_(3)-underset(("NEOPENTANE "))underset("2,2 Dimehtylpropane")underset(CH_(3))underset(|)overset( CH_(3))overset(|)(C)-CH_(3)`


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