1.

An alkane has a C/H-ratio (by mass) of 5.1428. Its molecular formula is

Answer»

`C_(5)H_(12)`
`C_(6)H_(14)`
`C_(8)H_(18)`
`C_(7)H_(10)`

Solution :The ratio of C/H in an alkane is 5.1428.
Alkanes have General formula `C_(n)H_(2n+2)`
The MASS ratio of `(C)/(H)` is `(12n)/(2n+2)` or `(6n)/(n+1)`
`(6n)/(n+1) = 5.1428`
`6n = 5.1428n + 5.1428 rarr 0.8572n = 5.1428`
`n = (5.1428)/(0.8572) = 6`
Molecular formula `= C_(6)H_(2n+2) = C_(6)H_(14)`.


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