1.

An alkaloidcontains 17.28% of nitrogen and its molecular mass is 162. The number of nitrogen atoms present in on molecule of alkaloid is

Answer»

five
four
three
two

Solution :Amount of nitrogen PRESENT in one MOLE of akaloid i.e., in 162 g `= (162xx17.28)/(100)`
`:.` No. of nitrogen atoms per molecule
`=(162xx17.28)/(100x24)=2`(APPROX.)


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