1.

An alkaloid contains 17-28% of nitrogen and itsmolecular mass is 162. The number of nitrogen atoms present in one molecule of alkaloid is :

Answer»

five
four
three
two

Solution :Amount of N PRESENT in 1 MOL of alkaloid
` = (162 XX 17.28)/(100)`
no. of N atoms present in 1molecule
` = (162 xx 17.28)/(100 xx 14) = 2 ` APPROX


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