1.

An alcoholic drink substance pH = 4.7 then OH ion concentration of this solution is (K_(w) = 10^(-14) mol^(2)//l^(2))

Answer»

`3 XX 10^(-10)`
`5 xx 10^(-10)`
`1 xx 10^(-10)`
`5 xx 10^(-8)`

Solution :pH = 4.7
pH + pOH = 14, pH = 14- 4.7 , pOH = 9.3
`[OH^(-)] = "ANTILOG" [-9.3] [OH^(-)] = 5 xx 10^(-10)`.


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