An alcohol (x) gives blue colour in victormayer's test and 3.7 g of X when treated with metallic sodium liberates 500 mLof hydrogen at 273 K and 1 atm pressure what will be the possible structure of X ?

An alcohol (x) gives blue colour in victormayer's test and 3.7 g of X

1.	An alcohol (x) gives blue colour in victormayer's test and 3.7 g of X when treated with metallic sodium liberates 500 mLof hydrogen at 273 K and 1 atm pressure what will be the possible structure of X ?
Answer» `CH_3CH(OH) CH_2CH_3` `CH_3-CH(OH) - CH_3` `CH_3-C (OH)-(CH_3)_2` `CH_3-CH_2-CH(OH) - CH_2-CH_3` Solution :`2R - OH + Na to 2RONa + 2H_2uarr` 2moles of alcohol gives 1 mole of `H_2` which OCCUPIES 22.4 L at 273 K and 1 ATM `:.` number of moles of alcohol `=(2"mole of R - OH")/(22.4L " of "H_2)xx560 mL = 0.05"moles"` `:.` number of moles `=("mass")/("molar mass")rArr "molar mass " = 3.7/0.05 = 74 g MOL^(-1)` GENERAL formual for `R - OH C_n H_(2n+1)-OH` `:.n (12) + (2n + 1) (1)+ 16 + 1= 74` `14n= 74 - 18` `14 n = 56` ` :. n = 56/4 = 4` The `2^@` alcohol which contains is `CH_2 CH(OH) CH_2 CH_3`