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An air bubble is situated at a distance of 0.08 m from the centre of a sphere of radius 0.12 m. When viewed from the nearest side it appears to be distance of 0.09 m from the centre. Find the refractive index of the material of the sphere. Where will the bubble appear to be when viewed from the farther side? |
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Answer» SOLUTION :Object distance of the air bubble from `P_(1)` `-u=0.12-0.08=0.04m ` for real object. `r_(1)=0.12 m (P_(1)O)` `v=-(0.12-0.09)` i.e., `v=-0.03 m (P_(1)B)` (i) using the FORMULA`(n_(0))/(-u)+(n_(1))/(v)= (n_(0)-n_(1))/(r)` .v. is negative because it is measured opposite to the DIRECTION of incident LIGHT. `(n_(0))/(0.04)+(1)/(-0.03)=(n_(0)-1)/(0.12)` `25n_(0)-33.33=(n_(0)-1)8.33` `25n_(0)-8.33n_(0)=33.33-8.33` `16.67n_(0)-25` `therefore n_(0)=1.4997` `n_(0)=1.50`  (II) u from `P_(2)=(0.12+0.08)=0.20m` `(1.5)/(0.2)+(1)/(v)=(1.5-1)/(0.12)` `7.5+(1)/(v)=4.167` `therefore (1)/(v)=-3.333` `therefore v= -(1)/(3.333)= -(1)/(10//3)` or `v=(-3)/(10)=-0.30m` |
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