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An aeroplane, when 3500m high passes vertically above another plane at an instant when the angles of elevation of the two aeroplanes from the same point on the ground are 45 degree and 30 degree respectively. Find the vertical distance between the two aeroplanes |
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Answer» Given : An AEROPLANE, when 3500m high passes vertically above another plane at an instant when the angles of elevation of the TWO aeroplanes from the same point on the ground are 45°and 30°respectively. To FInd : the vertical distance between the two aeroplanes Solution: Let say A Position of above plane B position of lower plane C is the point at ground below plane D is the point of observation AC = 3500 AB = distance between the two aeroplanes Tan 45 = AC/CD => 1 = 3500/CD => CD = 3500 Tan 30 = BC/CD => 1/√3 = BC/3500 => BC = 3500/√3 AB = AC - BC => AB = 3500 - 3500/√3 AB = 3500 (√3 - 1)/√3 = 1479.3 m LEARN more: the ANGLE of elevation of a vertical Tower observed from the age of a ... The angle of elevation of top of a pole from two points A and B on ... |
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