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An accelerating train is passing over a high bridge. A stone is dropped from the train at an instant when Its speed is 10 ms-1 and acceleration is 1ms-2 . Find the horizontal and vertical components of the velocity and acceleration of the stone one second after it is dropped. Take g = 10 ms-2 . |
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Answer» Horizontal acceleration = 0 (because there is no force acting on the stone in the horizontal direction to provide any acceleration) Horizontal velocity = 10 ms-1. Vertical acceleration = g = 10 ms-2. Vertical velocity = ut + \(\frac {1}{2} \) gt2 = 0(1) + \(\frac {1}{2}\) (10)(1)2 = 5 ms-1. |
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