1.

An α−particle of energy 3 MeV is scattered through 180∘ by gold nucleus. The distance of the closest approach is of the order of -The atomic number of gold is 79.

Answer»

An αparticle of energy 3 MeV is scattered through 180 by gold nucleus. The distance of the closest approach is of the order of -



The atomic number of gold is 79.



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