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An a.c source of frequency `1000 Hz` is connected to a coil of `(200)/(pi) mH` and negligible resistance. If effective current through the coil is `7.5 mA`, what is the voltage (in volt) across the coil ? |
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Answer» Correct Answer - 3 Here, `v = 1000 Hz, L = (200)/(pi) = (0.2)/(pi) H` `I_(upsilon) = 7.5 mA = 7.5 xx 10^(-3) A, E_(upsilon) = ?` As resistance of coil is negilgible, `:. E_(upsilon) = I_(upsilon) (X_(L)) = I_(upsilon) (2 pi v L)` `= 7.5 xx 10^(-3) (2 pi xx 1000 xx (0.2)/(pi)) = 3 V` |
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