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An `80 muC` charge is given to the `4muF` capacitor in the circuit shown in Fig. so thae upper plate A is positively charged. An unknown resistance R is connected in the left limb. As soon as the switch S in the central limb is closed, a current of 2 A flows through the `2Omega` resistor in the central limb. The capa citive time constant for the circuit is A. `56 mus `B. `8 mu s`C. `200 mu s`D. `40 mus ` |
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Answer» Correct Answer - D d. Potential difference across the central limb = 16 V = Potential difference across `16 Omega` = potential across the left limb. Current through `16Omega` = 1A Current through the left limb = 1 A and R = `11 Omega` `:. tau_(C) = (16/2+2) Omega xx (4 xx 10^(-6)) F = 40 mus` . |
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