1.

Amount of80% pure NaOH sample which is required to completely react with 42.6 gm Chlorine in hot condition according to given reaction NaOH + Cl_(2) rarrNaCl + H_(2)O + O_(2) is -

Answer»

48
60 gm
24 gm
30 gm

Solution :`2NaOH + Cl_(2) RARR 2NaCl + H_(2)O + (1)/(2) O_(2)`
`1.2` mole `0.6` mole
`n_(NaOH "pure required") = 1.2`
`W_(NaOH "pure") = 1.2 XX 40 = 48 gm`
`W_("impure sample") xx (80)/(100) = W_(NaOH "pure")`
`W_("sample") = 60 gm`


Discussion

No Comment Found