Saved Bookmarks
| 1. |
Amount of `80%` pure NaOH sample which is required to completely react with `42.6 gm` Chlorine in hot condition according to given reaction `NaOH + Cl_(2) rarrNaCl + H_(2)O + O_(2)` is -A. 48B. 60 gmC. 24 gmD. 30 gm |
|
Answer» Correct Answer - B `2NaOH + Cl_(2) rarr 2NaCl + H_(2)O + (1)/(2) O_(2)` `1.2` mole `0.6` mole `n_(NaOH "pure required") = 1.2` `W_(NaOH "pure") = 1.2 xx 40 = 48 gm` `W_("impure sample") xx (80)/(100) = W_(NaOH "pure")` `W_("sample") = 60 gm` |
|