1.

Amont the following the most reactive towards alcoholic KOH is

Answer»

`CH_(2)=CHBr`
`CH_(3)COCH_(2)CH_(2)Br`
`CH_(3)CH_(2)Br`
`CH_(3)CH_(2)CH_(2)Br`

Solution :A ELIMINATION of `Br^(-)` become easier due to the PRESENCE of CARBONYL group.


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