1.

Among the following observations, the correct one that differentiates between SO_(3)^(2-) and SO_(4)^(2-) is

Answer»

both form precipitate with `BaCl_(2),SO_(3)^(2-)` dissolves in HCI but `SO_(4)^(2-)` does not
`SO_(3)^(2-)`forms precipitate with `BaCl_2, SO_(4)^(2-)` does not
`SO_(4)^(2-)` forms precipitate with `BaCl_2`, `SO_(3)^(2-)` does not
both form precipitate with `BaCl_2, SO_(4)^(2-)` dissolves in HCl but `SO_(3)^(2-)` does not

Solution :`BaCl_2` forms WHITE ppt. with both `SO_(3)^(2-)` and `SO_(4)^(2-) . BaCl_(2) + SO_(3)^(2-) to underset("white ppt.")(BaSO_(3)) DARR + 2 Cl^(-)`
`BaCl_(2) + SO_(4)^(2-) to underset("white ppt.")(BaSO_(4)) darr + 2CL^(-)`
However , only `BaSO_(3)` dissolves in HCl through following reaction :
`BaSO_(3) + 2HCL to BaCl_(2) + SO_(2) uarr + H_(2) O`


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