1.

Among KO_(2),NO_(2)^(-),BaO_2 and NO_(2)^(+) unpaired electron is present in

Answer»

`NO_(2)^(+)` and `BaO_(2)`
`KO_(2)` and `BaO_(2)`
`KO_(2)` only
`BaO_(2)` only

Solution :`KO_(2)` because in `O_(2)^(-)` (superoxide ION) ONE UNPAIRED electron is present in the antibonding ORBITAL.


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