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Among all sectors of fixed perimeter, choose the one with maximum area. Then the angle at the center of this sector (i.e.,the angle between the boundibg radii) isA. `(pi)/(3)`B. `(3)/(2)`C. `sqrt(3)`D. 2 |
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Answer» Correct Answer - D Given that `2r_rtheta=P" "r=(p)/(2+theta)` area `=(1)/(2)r^(2)theta=(1)/(2)theta((P)/(2+theta))^(2)=(1)/(2)(P^(2)theta)/((2+theta)^(2))` `(dA)/(d theta)=0" "theta=2^(C)` |
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