Ammonium hydrogen sulphide dissociates as follows: [tex]NH_{4}HS(s) \rightleftharpoons NH_{3}(g)+H_{2}S(g), if the observed pressure of mixture is 1.12 atm. at 106°C. Find out the value of Kp for it.

Ammonium hydrogen sulphide dissociates as follows: [tex]NH_{4}HS(s) \r

1.	Ammonium hydrogen sulphide dissociates as follows: [tex]NH_{4}HS(s) \rightleftharpoons NH_{3}(g)+H_{2}S(g), if the observed pressure of mixture is 1.12 atm. at 106°C. Find out the value of Kp for it.
Answer» alculating the value of the CONCENTRATION is taken as 1 for the solid.“DALTON law” of “PARTIAL PRESSURE” states that the Observed Pressure is equal to the “sum of Pressure” of the gases.Given, Observed Pressure = 1.12 atm“Pressure of Ammonia” + “Pressure of HYDROGEN sulphide” = Observed Pressure“Pressure of Ammonia” + “Pressure of Hydrogen sulphide” = 1.12 atm