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Ammonia and oxygen react at high temperature as : `4NH_(a(g)) + 5O_(2(g))to 4NO_((g)) +6H_(2)O_((g))` In an experiment rate of formation of `NO_((g))` is `3.6 xx 10^(-3) mol L^(-1) s^(-1)` Calculate (a) Rate of disappearance of ammonia ( b) Rate of formation of water . |
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Answer» Correct Answer - (a) Rate of disappearance of `NH_(2) = 3.6 xx 10^(-3) mol L^(-1) s^(-1)` ( b) Rate of formation of `H_(2)O =5.4 xx 10^(-3) mol L^(-1) s^(-1)` Given : `4NH_(5(g)) +5O_(2(g)) to 4NO_((g)) + 6H_(2)O_((g))` `(d[NO])/(dt) = 3.6 xx 10^(-3) mol L ^(-1) s^(-1)` (a) `-(1)/(4) (d[NH_(3)])/(dt) =(1)/(4) (d[NO])/(dt)` `:.` Rate of disappearance of `NH_(3)` `=(-d[NH_(3)])/(dt) = (d[NO])/(dt)` `=3.6 xx 10^(-3) mol L^(-1) s^(-1)` `:.` Rate of formation of `H_(2)O` `=(d[H_(2)O])/(dt)=(6)/(4) (d[NO])/(dt)` `=(6)/(4) xx 3.6 xx10^(-3)` `=5.4 xx 10^(-3) mol L^(-1) s^(-1)` |
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