1.

Ammeter reads 2.0 a and the voltmeter reads 12v. how much energy is transferred in the resistor in 10 seconds.

Answer»

240JExplanation:GIVEN ,ammeter reading current is 2 AVOLTMETER reading 12 V OHM's law V=I.RR is V/IR is 12/2 is 6 ohmsenergy ,is i^2 .R.ttime is 10secenergy is (2)^2.6.10=4.6.10240 J



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