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Aluminium reacts with sulphure to form a aluminium sulphide . If 5.4 gm of Aluminium reacts with 12.8 gm sulphure gives 12 gm of aluminium sulphides , then the percent yield of the reaction is- |
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Answer» `2Al + 2S to Al_(2)S_(3)` Mole taken `{:((5.4)/(27) gm ,(12.8)/(32)),(=0.2,=0.4):}` `("mole taken")/("stoich coeff"){:((0.2)/(2),(0.4)/(3)),(=0.1,=0.133),((L.R.),):}` moles of `Al_(2)S_(3)` formed `=(1)/(2)xx0.2=0.1` mass=`0.1xx150=15` gm `%` yield `=("actual yield")/("theoritical yield")xx100=(12)/(15)xx100=80%` |
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