1.

Although geometries of and molecules are distorted tetrahedral, bond angle in water is less than that of ammonia. Discuss.

Answer»

rahedral geometry of Ammonia is,In the structure of Ammonia , the atom "N" is surrounded by "three (N-H) bond" PAIRS and only one "lone pair" of ELECTRON on the N atom. The "NUMBER of BONDING electrons" is more as compared to "lone pair" of electron, therefore, "repulsion" shown by one "lone pair" in is very less towards the three bond pairs. Hence, the "bond angle is 107°", nearer to "normal tetrahedral" "bond angle of 109°".The tetrahedral geometry of is given below.In this structure of , O atom is surrounded by the two O-H bond pairs and two lone pair of electrons. Therfore, repulsion is stronger between the bond and the lone pairs. Bond pairs is repelled "more" by the "lone pairs" which RESULTS in the decrease of "bond angle to 104°".Both the Ammonia and water have the tetrahedral geometry, but they have different bond angles. Hence, bond angle of "water" is less than "Ammonia".



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