1.

Although electron gain enthalpy of fluorine is less negative as compared to chlorine, fluorine is a stronger oxidizing agent than chlorine. Why?

Answer»

Solution :The.oxdising capability of a substance can be determined by its electrode potential Higher the electrode potential, stronger is the oxidizing agent. The electrode potential, in TURN, depends upon the following three factors:
(i) Bond dissociation enthalpy (ii) Electron gain enthalpy and (ii) HYDRATION energy. ALTHOUGH electron gain enthalpy of FLUORINE is less negative than that of chlorin e but (a) enthalpy of dissociation of F-F bond is lower than that of CI-Cl bond, and (6) Hydration enthalpy of Fion is higher than that of Crion. Because of these two REASON, electrode potential of `F_(2)` (+ 2.87 V) is much higher than that of `Cl_(2)` (+ 1.36 V) and hence `F_(2)` is a stronger oxidizing agent than `Cl_(2)`.


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