1.

`alpha`-particles of enegry `400 KeV` are boumbardel on nucleus of `._(82)Pb` . In scattering of `alpha`-particles, it minimum distance from nucleus will beA. 0.59 nmB. 0.59 ÅC. 5.9 ÅD. 0.59 pm

Answer» Correct Answer - D


Discussion

No Comment Found

Related InterviewSolutions