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`alpha`-particles of enegry `400 KeV` are boumbardel on nucleus of `._(82)Pb` . In scattering of `alpha`-particles, it minimum distance from nucleus will beA. 0.59 nmB. 0.59 ÅC. 5.9 ÅD. 0.59 pm |
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Answer» Correct Answer - D |
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