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All surfaces are smooth. Find the horizontal displacements of the block and wedge when the block slides down from top to bottom. |
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Answer» Solution :When the block SLIDES down on the smooth wedge, the wedge moves backwards. In the horizontal direction there is no external FORCE. `vecF_(x)=0` , `therefore vecP_(x)` = constant `vecP_(f) = vecP_(i)` (along x-axis) `mvecu + MvecV =0` `x_(1)` = FORWARD DISTANCE moved by the block along x-axis. `x_2` = backward distance moved by the wedge along x-axis. `mvecu=-MvecV, m(x_(1)/t) =Mx_(2)/t` `mx_(1) =Mx_(2).x_(1) =(ML)/(M+m) =(Ml cos theta)/(M+m)` `x_(2) =(mL)/(M+m) =(mlcos theta)/(M+m)` L can also be written as `l cos theta` |
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