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Aladder 10 m long reaches a window 8 m above theground. Find the distance of the foot of the ladderfrom base of the wall. |
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Answer» A| | | | B---------------------CAC=length of ladder=10mAB=height of window=8maccording to pathagorous theorem(H)^2=(P)^2+(B)^2(AC)^2=(AB)^2+(BC)^2(10)^2-(8)^2=(BC)^2100-64=(BC)^236=(BC)^2√36=BC6=BCdist of the foot of ladder from the base of wall is 6 m using Pythagoras theorem we know that a square is equal to b square + c square 10 square is equal to 8 8 square + x square so x is equal to 6 metre |
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