aka initially at rest pics of a velocity of 72 km per hour in 20 secon

1.	aka initially at rest pics of a velocity of 72 km per hour in 20 seconds if the mass of car is 1000 kilogram find the force developed by its engine distance covered by the car
Answer» u = 0 m/s V = 72 km/h = 72 5/18 m/s = 20 m/s t = 20 s As v = u + a t so, 20 = 0 + a 20 so, a = 20/20 = 1 m/s^2 Now mass = 1000 kg a = 1 m/s^2 and Force, F = ma so, F = 1000 * 1 = 1000 kg m/s^2 = 1 kN

aka initially at rest pics of a velocity of 72 km per hour in 20 seconds if the mass of car is 1000 kilogram find the force developed by its engine distance covered by the car

Answer»

u = 0 m/s

V = 72 km/h = 72 *5/18 m/s

= 20 m/s

t = 20 s

As v = u + a t

so, 20 = 0 + a * 20

so, a = 20/20 = 1 m/s^2

Now mass = 1000 kg

a = 1 m/s^2 and

Force, F = ma

so, F = 1000 * 1 = 1000 kg m/s^2

= 1 kN

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aka initially at rest pics of a velocity of 72 km per hour in 20 seconds if the mass of car is 1000 kilogram find the force developed by its engine distance covered by the car

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