Airplanes A and B are in the same vertical plane and flying with constant velocity. At time t=0 sec, an observer in A finds B at a distance of 500 m and moving perpendicular to the line of motion of A. If at t=t0 sec, A just escapes being hit by B , t0 in seconds is

Airplanes A and B are in the same vertical plane and flying with const

1.	Airplanes A and B are in the same vertical plane and flying with constant velocity. At time t=0 sec, an observer in A finds B at a distance of 500 m and moving perpendicular to the line of motion of A. If at t=t0 sec, A just escapes being hit by B , t0 in seconds is
Answer» Airplanes $A$ and $B$ are in the same vertical plane and flying with constant velocity. At time $t = 0 sec$ , an observer in $A$ finds $B$ at a distance of $500 m$ and moving perpendicular to the line of motion of $A$ . If at $t = t_{0} sec$ , $A$ just escapes being hit by $B$ , $t_{0}$ in seconds is

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Airplanes A and B are in the same vertical plane and flying with constant velocity. At time t=0 sec, an observer in A finds B at a distance of 500 m and moving perpendicular to the line of motion of A. If at t=t0 sec, A just escapes being hit by B , t0 in seconds is

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