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Air is pushed into a soap bubble of radius r to double its radius. If the surface tension of the soap solution is S, the work done in the process is (a) 8πr2S (b) 12πr2S (c) 16πr2S (d) 24πr2S. |
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Answer» The correct answer is (d) 24πr2S. Explanation: The surface tension S is equal to surface energy per unit area, S = U/A →U = SA The total area of the soap bubble =2*4πr² =8πr² The total surface energy of the original bubble =8πr²S The total surface area of the expanded bubble = 2*4π(2r)² =32πr² The total surface energy of the expanded bubble =32πr²S The work done in the process = increase in the surface energy of the bubble =32πr²S - 8πr²S =24πr²S |
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