Saved Bookmarks
| 1. |
Ahow that any positive integer is of the form 4n, 4n+1 or 4n+3, where n is a integer? |
|
Answer» As PER Euclid's division lemma if a and b are two positive integers then a = bq+r where 0 is LESS than or equal to r and r is less than b let positive INTEGER be a. and b= 4 hence a=4q+r where r is an integer greater than or equal to 0 and less than 4. hence r can be either 0,1,2 or 3 if r = 1 our equation becomes a=4q+r a=4q+1 this will always be an odd integer. if r=3 a=4q+r a=4q+3 this will always be an odd integer therefore, any odd integer is of the form 4q+1 or 4q+3 hence proved hope it helps plz mark this as the brainliest answer. |
|