⭐hey there!! Given that:➡ ∫ dx/√x+a - √x} Now rationalization of denominator, =>> 1/(√x+a - √x) × (√x+a + √x) /(√x+a +√x) => (√x+a + √x) /a ------------------(1)Now intigrating EXPRESSION (1) = 1/a ∫(√x+a + √x ) dx = 1/a { ∫√(x+a) dx + ∫√x dx } = 1/a ( 2/3 (x+a) ³/2 + 2/3 x³/2 ) => 2/3a { (x+a)³/2 + x³/2 } ans _______________________________________⭐Hope it will HELP u
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