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Ahemispherical bowl is made of steel 0.25cm thick. The inner radius of the bowl is 5cm22Find the outer curved surface area of the bowl |
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Answer» Answer: Step-by-step explanation: LET the Inner radius of hemispherical BOWL = 5 cm Thickness of the bowl = 0.25 cm ∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm = 5.25 cm Outer CSA of hemispherical bowl = 2πr2 = 2 x 22/7 x (5.25 cm)2 = 173.25 cm2 Therefore, the outer CURVED SURFACE AREA of the bowl is 173.25 cm2. Pls mark me the brainliest |
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