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Ae Calculate normality of 9.8 g ofH2So, in 250 ml ofsolution? |
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Answer» Moles of solute = Mass of solute / Molar mass of solute= 9.8 g / 98 g/mol= 0.1 mol Volume of solution = 25 cm³ = 0.025 Litres Molarity = Moles of solutes / Volume of solution in litres= 0.1 mol / 0.025 litres= 4 M Molarity of given solution is 4 M |
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