adj- `[{:( 1,0,2),(-1,1,-2),(0,2,1):}]=[{:(5,a,-2),(1,1,0),(-2,-2,b):}]`, then [a, b] is equal to-A. `[-4 1]`B. `[-4 -1]`C. `[4 1]`D. `[4-1]`

adj- `[{:( 1,0,2),(-1,1,-2),(0,2,1):}]=[{:(5,a,-2),(1,1,0),(-2,-2,b):}

1.	adj- `[{:( 1,0,2),(-1,1,-2),(0,2,1):}]=[{:(5,a,-2),(1,1,0),(-2,-2,b):}]`, then [a, b] is equal to-A. `[-4 1]`B. `[-4 -1]`C. `[4 1]`D. `[4-1]`
Answer» Correct Answer - 3 `(Adj A)_(12)= C_(21)= "cofactor of" a_(21)=- \|{:(0,2),(2,1):}\| =4` `(Adj A)_(33)= C_(33)= "cofactor of" a_(33)= + \|{:(1,0),(-1,1):}\| =1`

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adj- `[{:( 1,0,2),(-1,1,-2),(0,2,1):}]=[{:(5,a,-2),(1,1,0),(-2,-2,b):}]`, then [a, b] is equal to-A. `[-4 1]`B. `[-4 -1]`C. `[4 1]`D. `[4-1]`

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