Saved Bookmarks
| 1. |
ADC is drawn as an equilateral triangle on AC outside AABC. AD is parallel to BC. The bisector of D meets AB in E, say. Then BE is equal to (1) 1004 cm (2) 2008 cm (4) 502 cm (3) 0 VALID ANSWERS ONLY PLEASE |
|
Answer» if answer is right you have to FOLLOW me and make me BRAINLY answer Step-by-step EXPLANATION: ♥️♥️♥️ |
|