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AD is median of triangle ABC.The bisector of angle ADBand angle ADC meet AB andAC in E and F respectively.Prove that EF is parallel toBC. |
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Answer» In tri. DAE, DE Bisect angle ADBSo we haveDA/DB=AE/EB equ.1Similarly in tri. DAC, DE Bisect angle ADCwe getDA/DC=AF/FC(DC=DB)DA/DB=AF/FC equ.2From equ 1 and equ 2AE/EB= AF/FCIn tri ABCEF ¶ BE (... BPT) |
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