AD is an altitude of an isosceles tringleABC in which AB=AC.show that – InterviewSolution

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AD is an altitude of an isosceles tringleABC in which AB=AC.show that AD bisects BC

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Answer:

AD is an altitude of an isosceles TRIANGLE ABC in which AB = AC. (ii) AD bisects ∠A. ∴ BD = CD | C.P.C.T. ⇒ AD bisects BC.

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