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AD is an altitude of an isosceles triangle ABC in which AB = AC . show that AD bisects BC |
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Answer» ONG>ANSWER: In triangle ABD and triangle ACD we have, angle (i)ABD=angle ACD( angles opposite to equal sides are also equal) (ii) angle ADB=angle ADC (each 90') then triangle ABD is SIMILAR to triangle ACD (by AA similarity condition) THEREFORE BD=CD (by cpst). |
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