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Acthree bundled of shin308 m and 490 m longostingthat the bandles can be cut upin toleft over et392mwithout ang |
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Answer» Greatest LENGTH of the string that is to be CUT from the bundle can be found by taking H.C.F of all the three bundle lengths Three lengths are 392m, 308m, 490m Factors of 392 = 2x2x2x7x7 Factors of 308 = 2x2x7x11 Factors of 490 = 2x5x7x7 Common factors of the three are: 2 and 7 Therefore, H.C.F = 2x7 = 14 So, the strings in each bundle can be cut into 14m so that no string is 14m so that no string is left out.
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