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Acidified K2Cr207 solution turns green when S02 gas is passed through it due to formation of (a) Cr2(SO4)3 (b) CrO42- (c) Cr2(SO3)3 (d) CrSO4 |
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Answer» (a)cr2(so4)3Explanation:This reaction is taken as an EXPERIMENTAL VERIFICATION for the presence of sulphur dioxide gas (SO2). The equation for the reaction may be stated as follows:- K2CR2O7 + H2SO4 + 3SO2 ——— K2SO4 + Cr2(SO4)3 + H2O. The orange-coloured dichromate solution will turn green due to the formation of CHROMIUM(III) sulphate, Cr2(SO4)3. It is a redox reaction. Here:- The oxidising agent is potassium dichromate and the reducing agent is sulphur dioxide. Hope it HELPS!!!! |
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