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Acetyl bromide when reacts with excess of CH3MgI followed by treatment with saturated solution of NH4Cl it gives: (1) Acetone (2) Acetamide (3) 2-methyl-2-propanol (4) acetyl iodide |
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Answer» Acetyl bromide when reacts with excess of CH3MgI followed by treatment with saturated solution of NH4Cl it gives 2-methyl-2-propanol |
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