1.

Acetyl bromide when reacts with excess of CH3MgI followed by treatment with saturated solution of NH4Cl it gives: (1)  Acetone (2)  Acetamide (3)  2-methyl-2-propanol (4)  acetyl iodide 

Answer»

Acetyl bromide when reacts with excess of CH3MgI followed by treatment with saturated solution of NH4Cl it gives  2-methyl-2-propanol



Discussion

No Comment Found

Related InterviewSolutions