Acetic acid CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The – InterviewSolution

1.	Acetic acid CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H-bonds with a total strenght of 66.5 kJ per mol of dimer If at 25oC, the equilibrium constant for the dimerization is 1.3×103. Calculate △So for the reaction: 2CH3COOH(g)⇌(CH3COOH)2(g)
Answer» Acetic acid $C H_{3} C O O H$ can form a dimer $(C H_{3} C O O H)_{2}$ in the gas phase. The dimer is held together by two H-bonds with a total strenght of 66.5 kJ per mol of dimer If at $25^{o} C,$ the equilibrium constant for the dimerization is $1.3 \times 10^{3} .$ Calculate $△ S^{o}$ for the reaction: $2 C H_{3} C O O H (g) ⇌ (C H_{3} C O O H)_{2} (g)$

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