∠ACD is an exterior angle of ∆ABC. If m∠A=80°and m∠ACD = 140�

1.	∠ACD is an exterior angle of ∆ABC. If m∠A=80°and m∠ACD = 140°,thenfind the m∠B.
Answer» ANSWER: An exterior angle of a TRIANGLE is equal to the sum of the opposite interior angles. Hence, In this case ∠A and ∠B So, ∠A+∠B=140 ∘ as ∠A=∠B or,2∠A=140 ∘ ∠A=∠B=70 ∘ Step-by-step EXPLANATION: please mark me BRAINLIST

∠ACD is an exterior angle of ∆ABC. If m∠A=80°and m∠ACD = 140°,thenfind the m∠B.

Answer»

ANSWER:

An exterior angle of a TRIANGLE is equal to the sum of the opposite interior angles.

Hence, In this case ∠A and ∠B

So,

∠A+∠B=140

∘

as ∠A=∠B

or,2∠A=140

∘

∠A=∠B=70

∘

Step-by-step EXPLANATION:

please mark me BRAINLIST

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∠ACD is an exterior angle of ∆ABC. If m∠A=80°and m∠ACD = 140°,thenfind the m∠B.

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