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< ACD-1 30°1300A. 60°B. 70C, 50D. 80° |
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Answer» Jab AB=AC to <B=<C kyoki jab sammukh bhujae equal ho to unke angle bhi equal hoge. aur ab ham dekhte hai ki 130°+<ACB=180° (rekhik yugm angel) to <ACB=50°. ab eske baad <ABC=<ACB=50° ab ham pure triangle me dekhte hai, <CAB+<ABC+<ACB=180° [ ∆ ke tino angle ka addition]. <A+50°+50°=180° <A=180°-100°<A=80° |
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