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According to Pauling electronegativity scale, the percentage ionic character in A - B molecule may be given as: Percent ionic character =18(XB−XA)1.4, where XB and XA are electronegativities of B and A, respectively and XB>XA. If XA=1.84 XB=3.48, then the percentage ionic character in A - B is: (Given: (1.64)7/5=2.0) |
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Answer» According to Pauling electronegativity scale, the percentage ionic character in A - B molecule may be given as: Percent ionic character =18(XB−XA)1.4, where XB and XA are electronegativities of B and A, respectively and XB>XA. If XA=1.84 XB=3.48, then the percentage ionic character in A - B is: (Given: (1.64)7/5=2.0) |
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